Segregate a list of dictionary into multiple lists-CodePudding

I have a list of dictionaries which contains below data

[{
  "col1":"1",
  "col2":"a"
},{
  "col1":"2",
  "col2":"b"
},{
  "col1":"3",
  "col2":"c"
}]

Here my dictionary key fields are dynamic ( e.g. col1, col2).

I want to segregate this dictionary data into multiple list based on key field grouping. Result which i'm trying to achieve should look like this

{
  "col1":["1","2","3"],
  "col2":["a","b","c"]
}

Could anyone tell me how to do it in few lines rather then writing multiple for loops?

CodePudding user response：

What about this solution? You could try this collections.defaultdict() to group all items with the same key: To make it readable it's perfect fine to use loops.

from collections import defaultdict

dd = defaultdict(list)

lst = [{
  "col1":"1", "col2":"a"
},{
  "col1":"2", "col2":"b"
},{
  "col1":"3", "col2":"c"
}]

for d in lst:
    #print(d)  # d is a dict
    for k, v in d.items():
        dd[k].append(v)
        
print(dd)

Results:

defaultdict(<class 'list'>, {'col1': ['1', '2', '3'], 'col2': ['a', 'b', 'c']})