I have a simple table that contains trips over different dates.
trip_id | start_date | end_date |
---|---|---|
160320 | 2017-12-31 20:40:25 UTC | 2017-12-31 20:45:25 UTC |
160321 | 2018-01-12 21:01:51 UTC | 2018-01-12 22:01:51 UTC |
I simply want to create a SQL query that shows these fields.
- year
- month
- trips_this_month,
- trips_previous_month
- difference_from_previous_month (count_this_month - count_previous_month)
- is_increased (is a boolean column that is true if we saw an increase, false otherwise) Update: I could wrap up my head and write a simple query to obtain them, but I still feel I can optimize this query. Any help will be appreciated.
SELECT
year,
month,
trips_this_month,
trips_previous_month,
case when difference_from_previous_month < 0 then false else true end as is_increased
FROM
(SELECT
year,
month,
number_of_trips AS trips_this_month,
LAG(number_of_trips,1,0) over (order by year,month) AS trips_previous_month,
number_of_trips - LAG(number_of_trips,1,0) OVER(order by year,month) AS difference_from_previous_month,
FROM(
SELECT EXTRACT(Month FROM start_date) AS month,
EXTRACT(Year FROM start_date) AS year,
COUNT(*) as number_of_trips
FROM a_table
group by month ,year
)
order by year, month
limit 100
)
But I could not help myself to do more. I appreciate with further helps to complete it.
CodePudding user response:
Try this:
WITH RECURSIVE cte AS (
SELECT MIN(start_date) minstdt, MAX(start_date) maxstdt FROM mytable
UNION ALL
SELECT minstdt INTERVAL 1 MONTH, maxstdt FROM cte
WHERE minstdt INTERVAL 1 MONTH <= maxstdt )
SELECT year,
month,
number_of_trips,
number_of_trips-IFNULL(prev_month_number_of_trips,0) AS This_month_vs_prev_month,
IF(number_of_trips > prev_month_number_of_trips,1,0) AS Is_increased
FROM
(SELECT
YEAR(cte.minstdt) AS year,
MONTH(cte.minstdt) AS month,
SUM(CASE WHEN start_date IS NULL THEN 0 ELSE 1 END) AS number_of_trips,
LAG(SUM(CASE WHEN start_date IS NULL THEN 0 ELSE 1 END))
OVER (ORDER BY YEAR(cte.minstdt), MONTH(cte.minstdt)) AS prev_month_number_of_trips
FROM cte
LEFT JOIN mytable
ON YEAR(cte.minstdt)=YEAR(start_date)
AND MONTH(cte.minstdt)=MONTH(start_date)
GROUP BY year, month) V
ORDER BY year, month;
- I've used recursive common table expression (
cte
) to generate date based on the minimum and maximum date appeared instart_date
of the table. - I've replaced
EXTRACT()
withYEAR()
andMONTH()
functions to make is slightly shorter. - I
LEFT JOIN
thecte
with the data table.
See if you can work with this.
CodePudding user response:
Consider a self-join to compare current and previous months aggregations using a normalized first-day of month date:
WITH sub AS (
SELECT
DATE_SUB(
DATE_ADD(LAST_DAY(start_date), INTERVAL 1 DAY),
INTERVAL 1 MONTH
) AS month_year,
COUNT(*) AS number_of_trips
FROM a_table
GROUP BY month_year
), calc AS (
SELECT
YEAR(curr.month_year) AS year,
MONTH(curr.month_year) AS month,
COALESCE(curr.number_of_trips, 0) AS trips_this_month,
COALESCE(prev.number_of_trips, 0) AS trips_previous_month
FROM sub AS curr
LEFT JOIN sub AS prev
ON prev.month_year = DATE_SUB(curr.month_year, INTERVAL 1 MONTH)
)
SELECT
year,
month,
trips_this_month,
trips_previous_month,
trips_this_month - trips_previous_month AS difference_from_previous_month,
(trips_this_month - trips_previous_month) > 0 AS is_increased
FROM calc