In my browser console:
x='"AbCd123|999"';
"\"AbCd123|999\""
x.match(/[^\""|] /)
Array [ "AbCd123" ]
Using sed in the shell:
(base) balter@winmac:~/winhome/CancerGraph/TCGA$ echo '"AbCd123|99999"' | sed -En 's/([^\"|] )/\1/p'
"AbCd123|99999"
(base) balter@winmac:~/winhome/CancerGraph/TCGA$ echo '"AbCd123|99999"' | sed -En 's/\"([^|] )/\1/p'
AbCd123|99999"
CodePudding user response:
That is all fine, because sed
command used with -n
option and p
flag only prints the text that was not matched the result of the successful replacement.
That means, you can get your "match" with
echo '"AbCd123|99999"' | sed -En 's/["|]*([^"|] ).*/\1/p'
See the online demo.
Here, the pattern gets to the first char that is not "
and |
with ["|]*
, then the ([^"|] )
part captures one or more chars other than "
and |
, and then .*
matches the rest of the string.
Everything that was matched but not captured is removed as you only ask to p
rint the \1
, the Group 1 value (captured with ([^"|] )
).