Java method that only selects the Regexp match instead of replacing it?-CodePudding

Java doesn't seem to have a method where I can only get the matched string.

'content.append(line.replaceAll("(?<=name=\").*(?=\")", ""));`

(this only leaves (name="") It worked on those online tools to select the name itself within the quotes but there's no method that I can use to set my string to only the pattern that matches, instead of the pattern being replaced by something else.

It just leaves name="", but I want to remove name="" only, and leave the actual name inside the quotes.

Any ideas on a method that won't require me to rewrite this over and over again.

Here's the document I'm trying to edit, in case it helps:

version="1.4.4.2"
tags={
    "Total Conversion"
}
name="Princes of Darkness"
supported_version="1.4.*"
path="C:/Users/Flint/Documents/Paradox Interactive/Crusader Kings III/mod/princesofdarkness"
remote_file_id="2216659254"

I only want - Princess Of Darkness in my string, without any quotes.

CodePudding user response：

You can use Matcher#find and Matcher#group.

Matcher matcher = Pattern.compile("(?<=name=\").*(?=\")").matcher(line);
if (matcher.find()) 
    content.append(matcher.group());

CodePudding user response：

To remove name=, do this:

line.replaceAll("^name=(?=\\")", "")

This matches name= when at the start of the line (via ^) and when the following character is a quote (via (?=\")).

In context of your code:

content.append(line.replaceAll("^name=(?=\\")", ""));