How to merge dictionaries in list according to specify condition using python code-CodePudding

I have some switches in the stack. There is only one IP of this stack, but there are several switches, so I need collect IP addr and all switch IDs of this stac in dict.

I have one list with dicts:

list = [
{'id': '107', 'name': sw1, 'ip': '10.10.10.5', 'stack_id': 'sw1', 'manufcturer': 'cisco'}, 
{'id': '352', 'name': sw2, 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'}, 
{'id': '125', 'name': sw3, 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'}, 
{'id': '90', 'name': sw4, 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'}, 
{'id': '148', 'name': sw5, 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'}, 
{'id': '45', 'name': sw6, 'ip': 'None', 'stack_id': 'sw6', 'manufcturer': 'cisco'} ]

I need compare key stack_id, if values of this keys are equal in this dicts, then need to create nested dicts like present bellow:

list2 = [
  {dev1 : {'ip': '10.10.10.5', 'id1': '107' 'id2': '352', 'id3': '125', 'id4': '90', 'id5': '148'}}
, {'id': '45', 'name': sw6, 'ip': 'None', 'stack_id': 'sw6', 'manufcturer': 'cisco'}
, ...
]

Please help. I'm a new with python and didn't find similar solution for this task. Thank you!

CodePudding user response：

below my proposal, and one small remark, never use the list keyword in your code, because it can break your code on unexpected places :)

l = [
{'id': '107', 'name': "sw1", 'ip': '10.10.10.5', 'stack_id': 'sw1', 'manufcturer': 'cisco'},
{'id': '352', 'name': "sw2", 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'},
{'id': '125', 'name': "sw3", 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'},
{'id': '90', 'name': "sw4", 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'},
{'id': '148', 'name': "sw5", 'ip': 'None', 'stack_id': 'sw1', 'manufcturer': 'cisco'},
{'id': '45', 'name': "sw6", 'ip': 'None', 'stack_id': 'sw6', 'manufcturer': 'cisco'} ]


from pprint import pprint
tmp = dict()
for i in l:
    tmp.setdefault(i["stack_id"],[])
    tmp[i["stack_id"]].append(i)

pprint(tmp)

Result:

{'sw1': [{'id': '107',
          'ip': '10.10.10.5',
          'manufcturer': 'cisco',
          'name': 'sw1',
          'stack_id': 'sw1'},
         {'id': '352',
          'ip': 'None',
          'manufcturer': 'cisco',
          'name': 'sw2',
          'stack_id': 'sw1'},
         {'id': '125',
          'ip': 'None',
          'manufcturer': 'cisco',
          'name': 'sw3',
          'stack_id': 'sw1'},
         {'id': '90',
          'ip': 'None',
          'manufcturer': 'cisco',
          'name': 'sw4',
          'stack_id': 'sw1'},
         {'id': '148',
          'ip': 'None',
          'manufcturer': 'cisco',
          'name': 'sw5',
          'stack_id': 'sw1'}],
 'sw6': [{'id': '45',
          'ip': 'None',
          'manufcturer': 'cisco',
          'name': 'sw6',
          'stack_id': 'sw6'}]}