I cannot send form by using sweetalert 2-CodePudding

I read a lot of posts on this but nothing work on my side

I have the follow php code:

<?

if( isset($_POST['btn-login']) ) {    
$mails = new PHPMailer;
$content = "xxxx";
$mails->IsSMTP();
$mails->send();
}

?>


<form name="form1" id="form1"  method="post">
<input   name="oggetto" id="oggetto" required placeholder="Oggetto"  >
<input  type="submit" name="submit" id="btn-submit" value="Invia"/>
</form>

with this script:

<script>

  $('#btn-submit').on('click',function(e){
                e.preventDefault();
                var form = $('.form1');
                console.log("hello");
                swal.fire({
                    title: "Inviare il msg?",
                    icon: 'warning',
                    showCancelButton: true,
                    confirmButtonColor: "#DD6B55",
                    confirmButtonText: "Si",
                }).then(function (result){
                    if(result.value === true){
                    console.log(form);
                    $('.form1').submit();
                  }
                });
            });
</script>

i can see the popup with sweet alert but when i click on the submit button the form doesn't work. Pls don't consider parameters of PHPMailer (that are just to understand the structure)

JFiddle example is here

Any help on this? thanks in advance

CodePudding user response：

@brombeer i think the problem is in calling the form.submit after the success of sweetalert...

CodePudding user response：

The NUMBER ONE error is having ANYTHING with the reserved word submit as id or name in your form.

If you plan to call .submit() on the form AND the form has submit as id or name on any form element, then you need to rename that form element, since the form’s submit method/handler is shadowed by the name/id attribute.

Also, since the form is submitted via javascript, for some reason, the submit button will not be sent to the server so if( isset($_POST['btn-login']) ) will not work. You can instead put that name value in a hidden input field and use it on the server.

This worked for me

$(document).ready(function(){
    $('#btn-submit').on('click', function(e){
        e.preventDefault();

        swal.fire({
            title: "Inviare il msg?",
            icon: 'warning',
            showCancelButton: true,
            confirmButtonColor: "#DD6B55",
            confirmButtonText: "Si",
        }).then(function (result){
            if(result.value === true){
                $('.form1').submit();
            }
        });
    });
});

<?php

if( isset($_POST['submit-login']) ){
    print_r($_POST);
}

?>

<link rel="stylesheet" type="text/css" href="https://cdnjs.cloudflare.com/ajax/libs/limonte-sweetalert2/11.1.9/sweetalert2.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdn.jsdelivr.net/npm/sweetalert2@10/dist/sweetalert2.all.min.js"></script>

<form id="form1"  method="post">
    <input type="hidden" name="submit-login">
    <input   name="oggetto" id="oggetto" required placeholder="Oggetto">
    <input type="submit"  id="btn-submit" value="Invia" />
</form>