When I assign anonymous function to the variable using ternary operator with the true condition, I can call the variable as a normal function.
>>> a = lambda x, y: x y if True else lambda x, y: x * y
>>> a(1, 2)
3
But when the condition is false and the function to be assigned is after the word else
, I get something like this. I have no idea what mechanisms stand behind such a weird behaviour. Is there any syntax nuances? Or any possibility to use ternary operator in cases like this one?
>>> a = lambda x, y: x y if False else lambda x, y: x * y
>>> a(1, 2)
<function <lambda>.<locals>.<lambda> at 0x10916aee0>
CodePudding user response:
You need to use parentheses to indicate your meaning.
You mean
(lambda x, y: x y) if True
else (lambda x, y: x * y)
but you have
lambda x, y:
(x y if True
else lambda x, y: x * y)
The ... if ... else ...
operator has higher precedence than lambda
. See https://docs.python.org/3/reference/expressions.html#operator-precedence.