I have a list of words and a list of letters:

list = ["clyde","tool","ball","window"]
letters = ["c","t"]

I want to filter the first list by removing the word if it has any letters from the second list.

list = ["ball","window"]

CodePudding user response：

You can use filter() and all() to only retain words that do not have any letters that appear in letters (as an aside, you shouldn't use list as a variable name, as it shadows the list builtin):

data = ["clyde","tool","ball","window"]
letters = ["c","t"]

result = list(filter(lambda x: all(c not in x for c in letters), data))

# Prints ['ball', 'window']
print(result)

CodePudding user response：

Using set objects makes this pretty straight forward:

words = ["clyde", "tool", "ball", "window"]
letters = {"c", "t"}  # a set object

filtered_words = [word for word in words if not letters.intersection(word)]

CodePudding user response：

You can also do it like this :-

list = ["clyde","tool","ball","window"] 
letters = ["c","t"] 
out = [i for i in list if not i[0] in letters]
print(out)

Output:

['ball', 'window']

CodePudding user response：

Simple to understand code example

words_list = ["clyde","tool","ball","window"]
letters = ["c","t"]
elements_to_remove=[]
# loop for each word in main list
for word in words_list:
    #check for each letter if present in restricted letters
    for letter in word:
        if letter in letters:
            #if present store word to remove
            elements_to_remove.append(word)
            break

#remove prohibited words from the list      
for element in elements_to_remove:
    words_list.remove(element)
print(words_list)

CodePudding user response：

This problem can be solved using List Comprehensions，like this：

lst = ["clyde","tool","ball","window"]
letters = ["c","t"]

res = [data for data in lst if all(item not in data for item in letters)]
print(res)

Please note that it is better not to have variables with the same name as keywords in python,so I changed the list to lst