edit(fixed): so the error seems to appear because writing a 20 character array will add \0 as a character and become a 21 character array.

I'm trying to detect a char c and remove it from a string char[20] s, but if I wrote a string s of 20 characters exactly, the debug error pops but the code works fine. why does it happen?

#pragma once
#include<iostream>
#include<cstring>
using namespace std;
#pragma warning(disable:4996)

void resultt(char c, char s[]) {
    while (*s != '\0') {
        if (*s == c) {
            strcpy(s,(s 1));
            continue;
        }
        s  ;
    }
}

void mainn() {
    char c; char s[20];
    cout << "enter a string : ";
    cin >> s;
    cout << "enter the character : "; cin >> c;
    resultt(c, s);
    cout << s;
}

I call that function like this resultt(c,s) and cout<<s at last.

CodePudding user response：

the error seems to appear because writing a 20 character array will add \0 as a character and become a 21 character array. by writing for example qwertyuiopqwertyuiop which is 20 characters, there won't be enough space in the array for the \0 character, so you should write a 19 character word (or less) or increase the array to 21