Python: How to add a zero after every digit in a number for numbers in list to create a new list-CodePudding

Background: I am trying out doing a fun little monthly computational math puzzle.

I am at a stage that I have a list comprised of binary numbers and I am looking to write a python program that takes all the numbers in the list and appends a zero behind each digit and makes a new list.

1--> 10, 101---> 100010, 10---->1000.

CodePudding user response：

string approach

This is easily achieved using strings:

def add0(n):
    s = str(n)
    return '0'.join(list(s)) '0'

add0(101)

Output: 100010

numerical approach

You need to play with divmod and powers of ten

def add0(n):
    out = 0
    exp = 0
    while n>0:
        n,r = divmod(n,10)
        out  = 10**(2*exp 1)*r
        exp  = 1
    return out

add0(12345)
# 1020304050

CodePudding user response：

The easiest way for me was:

list = [1, 0]
new_list = []

for i in list:
    new_list.append(i)
    new_list.append(0)
   
print(list)
print(new_list)

CodePudding user response：

There are more efficient ways, but I just don't feel like thinking, so here it is, it adds 0 using for loop add it to list, then join all the elements from the list

while True:
    ff = input("input disits: ")
    ff2 = []
    for i in ff:
        ff2.append(i '0')
    print(''.join(ff2))

Or another way is adding string

while True:
    ff = input("input disits: ")
    ff2 = ''
    for i in ff:
        ff2  = i '0'
    print(ff2)

Want int answer? do print(int(''.join(ff2))) or print(int(ff2))

while True:
    print(int(''.join([i '0' for i in input("input disits: ")])))