I am working on a large Pandas DataFrame which needs to be converted into dictionaries before being processed by another API.
The required dictionaries can be generated by calling the .to_dict(orient='records')
method. As stated in the docs, the returned value depends on the orient
option:
Returns: dict, list or collections.abc.Mapping
Return a collections.abc.Mapping object representing the DataFrame. The resulting transformation depends on the orient parameter.
For my case, passing orient='records'
, a list of dictionaries is returned. When dealing with lists, the complete memory required to store the list items, is reserved/allocated. As my dataframe can get rather large, this might lead to memory issues especially as the code might be executed on lower spec target systems.
I could certainly circumvent this issue by processing the dataframe chunk-wise and generate the list of dictionaries for each chunk which is then passed to the API. Furthermore, calling iter(df.to_dict(orient='records'))
would return the desired generator, but would not reduce the required memory footprint as the list is created intermediately.
Is there a way to directly return a generator expression from df.to_dict(orient='records')
instead of a list in order to reduce the memory footprint?
CodePudding user response:
There is not a way to get a generator directly from to_dict(orient='records')
. However, it is possible to modify the to_dict
source code to be a generator instead of returning a list comprehension:
from pandas.core.common import standardize_mapping
from pandas.core.dtypes.cast import maybe_box_native
def dataframe_records_gen(df_):
columns = df_.columns.tolist()
into_c = standardize_mapping(dict)
for row in df_.itertuples(index=False, name=None):
yield into_c(
(k, maybe_box_native(v)) for k, v in dict(zip(columns, row)).items()
)
Sample Code:
import pandas as pd
df = pd.DataFrame({
'A': [1, 2],
'B': [3, 4]
})
# Using Generator
for row in dataframe_records_gen(df):
print(row)
# For Comparison with to_dict function
print("to_dict", df.to_dict(orient='records'))
Output:
{'A': 1, 'B': 3}
{'A': 2, 'B': 4}
to_dict [{'A': 1, 'B': 3}, {'A': 2, 'B': 4}]
For more natural syntax, it's also possible to register a custom accessor:
import pandas as pd
from pandas.core.common import standardize_mapping
from pandas.core.dtypes.cast import maybe_box_native
@pd.api.extensions.register_dataframe_accessor("gen")
class GenAccessor:
def __init__(self, pandas_obj):
self._obj = pandas_obj
def records(self):
columns = self._obj.columns.tolist()
into_c = standardize_mapping(dict)
for row in self._obj.itertuples(index=False, name=None):
yield into_c(
(k, maybe_box_native(v))
for k, v in dict(zip(columns, row)).items()
)
Which makes this generator accessible via the gen
accessor in this case:
df = pd.DataFrame({
'A': [1, 2],
'B': [3, 4]
})
# Using Generator through registered custom accessor
for row in df.gen.records():
print(row)
# For Comparison with to_dict function
print("to_dict", df.to_dict(orient='records'))
Output:
{'A': 1, 'B': 3}
{'A': 2, 'B': 4}
to_dict [{'A': 1, 'B': 3}, {'A': 2, 'B': 4}]