I have the following string and i need to get the content inside the string.

I have tried the following Regex . But it comes with the outer paranthesis.

Input string :

           Test (1001,Sunday)

Regex Pattern

          Regex : (([^,] ),([^,)] )) 
          Output : (1001
       

But I require output like the following

         match[0]=1001 , match[1] = sunday.

I also tried the following patterns but ended up with build warnings.

          (Test \(([^)] )\)) : 

Due to escape sequence i was not able to build it without warnings.

The above Regex works fine for me but i get compilation warnings

CodePudding user response：

If you wanted to do this all with Regex, just match the parenthesis section.

\((\S ?),(\S ?)\)

Then group 1 will be "1001" and group 2 will be "Sunday".

var input = "Test (1001,Sunday)";
var pattern = new Regex(@"\((\S ?),(\S ?)\)");
var match = pattern.Match(input);

Console.WriteLine(match.Groups[1].Value);
Console.WriteLine(match.Groups[2].Value);

In this pattern I'm using \S, which is "any non-whitespace character". You can change this as need be. For example, if you know that the first group is always going to be digits, change to \d.

---

Another way of doing this that doesn't involve Regex (thanks Trevor for the idea), it to search for the only ( and ) characters, substring, and split by commas.

var input = "Test (1001,Sunday)";
var start = input.IndexOf('(')   1; //  1 to avoid including "("
var end = input.LastIndexOf(')');
var data = input[start..end];
var segments = data.Split(',');

foreach (var segment in segments)
{
    Console.WriteLine(segment);
}

CodePudding user response：

The pattern (([^,] ),([^,)] )) has 3 capture groups, where group 2 for example matches any character except a comma [^,] .

That negated character class will also match the opening (

What you might do is use 2 capture groups instead, exclude the parenthesis as well, and also match the opening and closing parenthesis in the example string.

\(([^,()] ),([^,()] )\)

See a .NET Regex demo and a C# demo.

---

If there can be more than 2 values between the parenthesis, you can make use of a capture group with the same name, and the Group.Captures Property.

\((?<val>[^,()] )(?:,(?<val>[^,()] ))*\)

The pattern matches:

• \( Match (
• (?<val>[^,()] ) Group val, match 1 or more occurrences of any char except , ( )
• (?: Non capture group to capture as a whole
  • , Match literally
  • (?<val>[^,()] ) Again group val with the same pattern
• )* Close the non capture group and optionally repeat to also allow a single value
• \) Match )

See a .NET regex demo and a C# demo.

var pattern = @"\((?<val>[^,()] )(?:,(?<val>[^,()] ))*\)";
var str = "Test (1001,Sunday)";
var strings = Regex.Match(str, pattern).Groups["val"].Captures.Select(c => c.Value);

foreach (String s in strings)
{
    Console.WriteLine(s);
}

Output

1001
Sunday

CodePudding user response：

If your string is always of the pattern

a(b,c)

And you want b and c in different variables it might be simplest to just split on multiple delimiters:

var input = "Test(1001,sunday)";
var bits = input.Split('(',')',',');

Now your "1001" is in bits[1] and "sunday" is in bits[2]

---

You mentioned that your input is an an array:

var input = new []{
  "Test(1001,sunday)",
  "Test(1002,monday)"
};

So you could:

var r = input.Select(i => {
  var bits = i.Split('(',')',',');
  return new { Num = bits[1], Day = bits[2] };
});

This would produce an enumeration of anonymous types objects where each one has your requested data in its Num/Day properties

foreach(var a in r)
  Console.Write($"Num is {a.Num} and Day is {a.Day}");