I need to get the id from all the child elements, which are in the parent class = "demo", but if the parent class = "demo" has id = "simone" I don't need to get the child id. How to achieve this?
If is simone, don't get children's id, else get children's id?
var name;
var divsname = document.querySelectorAll('.demo *');
divsname.forEach(function(div){
if (div.hasAttribute("id")) {
name = "Name: " div.getAttribute("id") ", ";
}else{
}
document.getElementById("get-demo").innerHTML = name;
console.log(name);
});
<div id="maja" ><div id="maja-child"></div></div>
<div id="alex" ><div id="alex-child"></div></div>
<div id="simone" ><div id="simone-child"></div></div>
<div id="pit" ><div id="pit-child"></div></div>
<div id="get-demo"></div>
CodePudding user response:
welcome to stackoverflow borma ;)
just use parentElement.getAttribute("id"),
ParentElement() will retrun parent of child element you can use exeption
div.parentElement.getAttribute("id") !== "simone"
will return false if id is simone.
Example
if (div.hasAttribute("id") && div.parentElement.getAttribute("id") !== "simone") {
name = "Name: " div.getAttribute("id") ", ";
}
This full script
window.onload = () =>
{
var name = '', divsname = document.querySelectorAll('.demo *');
divsname.forEach(function(div){
if (div.hasAttribute("id") && div.parentElement.getAttribute("id") !== "simone") {
name = "Name: " div.getAttribute("id") ", ";
}
document.getElementById("get-demo").innerHTML = name;
});
}
CodePudding user response:
You can use the css :not selector and exclude the id simone.
var name;
var divsname = document.querySelectorAll('.demo:not(#simone) *');
divsname.forEach(function(div){
if (div.hasAttribute("id")) {
name = "Name: " div.getAttribute("id") ", ";
}else{
}
document.getElementById("get-demo").innerHTML = name;
console.log(name);
});
<div id="maja" ><div id="maja-child"></div></div>
<div id="alex" ><div id="alex-child"></div></div>
<div id="simone" ><div id="simone-child"></div></div>
<div id="pit" ><div id="pit-child"></div></div>
<div id="get-demo"></div>
CodePudding user response:
You can use @jkoch answer or if you need to do something with any div with id 'simone' you can filter it within the forEach callback function. The name variable I set to a blank "" to avoid getting 'result' in the name variable.
var name = ""
var divsname = document.querySelectorAll('.demo');
divsname.forEach(function(div){
if (div.id !== 'simone') {
name = "Name: " div.id ", ";
}else{
//code if you want to do something with simone id
}
document.getElementById("get-demo").innerHTML = name;
console.log(name);
});
CodePudding user response:
This should work.
document.querySelectorAll(".demo").forEach((item) => {
if (item.id !== "simone") {
console.log(item.firstChild.id);
}
});
<div id="maja" ><div id="maja-child"></div></div>
<div id="alex" ><div id="alex-child"></div></div>
<div id="simone" ><div id="simone-child"></div></div>
<div id="pit" ><div id="pit-child"></div></div>
<div id="get-demo"></div>