How to print numbers in the following pattern with .NET-CodePudding

I have a program in C# that takes an integer argument from the command line and prints number patterns from 1 to that number in the format below for a number like 5.

You can see that for each number, that number is printed the same time as itself, like for three it’s been printed on a single line three times, and so and so forth.

I have tried to develop a function that multiplies an integer with a string with String.Concat(string param, int n) and returns that string to another function with a loop that prints the expected output to terminal.

My code prints like below:

For a sample integer input like 5.

What am I doing wrong and what should I do to correct my loop so it gives me the expected output?

Code

static string MakeALine(int k){
    // All this function does is to convert the
    // integer argument to a string and multiply
    // it with itself and returns it
    return String.Concat(k.ToString,k);
}

// The function below contains a loop that should
// invoke the make a line correctly to achieve
// the desired output above
static string MakeLines(int arg){
    // The argument is the command line argument supplied
    string outp = "";
    // I have a problem in the loop below. How can I fix it?
    for(int k=1; k<=arg; k  ){
        // Call makeALine and pass k as argument and append to the return string
        outp  = MakeALine(k)   "\n";
    }
    return outp;
}

What am I doing wrong?

CodePudding user response：

The problem is in the MakeALine method. You actually concat the number with itself, so for input 1 you actually get "1" "1".

Instead you should repeat the string representation of your number k times. For this you can use Enumerable.Repeat in the following way:

static string MakeALine(int k)
{
    return String.Concat(Enumerable.Repeat(k.ToString(),k));
}

CodePudding user response：

Try with this:

private static string makeLines(int k)
{
    string outPut = "";
    for(int i = 1 ; i < k 1 ; i  )
    {
        outPut  = string.Concat(Enumerable.Repeat(i, i))   "\n";
    }
    return outPut;
}