VSCode regex change space-separated decimals to be separeated by commas?-CodePudding

I have some text like this: 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 [-0.01357987 0.99989218 -0.00558794] [ 0.50810066 0.81535196 -0.27755161] -18017079.1047535 10307726.258588774 -23524317.110919423 22838.17515528947 36648.54674929567 -12475.426190771163 20757272.462656207 5 5 0.005 0 5 2 0.0005 3 -98.28031520537542 29.516134353642414 19998.73252382984 -0.0055879708379507065 -0.06085533474930652 359.2218946628823 818.306543386653 2.7826806154507513 8.100054108045068 -0.7584403000503389 -0.02994106840115437 -0.0628111825224635 0.058338781314879004 242.42818865783832 0.0 0.8063781178568004 -2.6036838124274486 0.0 -0.734866228020307 -0.062 -0.062 0.008726849073962957 0.0 123.16666557966661 1.2292998660484957e-09 0.0 0.0 25619.0 Allies [-0.06088792 0.00475117 0.9981333 ] 0.5064766089927465 0.3371159370714128 0.6267890628740791 1.6191164404478644 -4.404605641298986 1.0085164509526248 0.9403428264947271 1.002228406356249 0.5911076156375097 0.04943091153402836 -0.12347543075231103 -0.031096345163790243 -0.1049357617938111 0.024866980145114622 0.04861966645392242

I would like to split them by space, but preserving the list inside. So I am considering first replace spaces inside the lists with commas(trimming the beginning and ending spaces if any). And then I could do a simple splitting by spaces. Is this doable via regex on VSCode? One can write a verbose Python script to handle this logic. But I think that would be dumb and not elegant.

CodePudding user response：

There is no need for your roundabout approach of replacing some spaces with commas. You could write the following in Python. I expect it would be similar in VSCode.

import re

str = "1 0 [-0.01  0.99]\n6.34 [0.501 -0.27] -18.10\n10.25"

rgx = r'\[.*?\]|\S '

re.findall(rgx, str)
  #=> ['1', '0', '[-0.01  0.99]', '6.34', '[0.501 -0.27]', '-18.10', '10.25']

Regex demo^_<-_\(ツ)/^_->Python demo

The regular expression has the following elements.

\[   # match left bracket
.*?  # match zero or more characters lazily
\]   # match right bracket
|    # or
\S   # match one or more non-whitespace characters, as many as possible

As an aside, when contemplating hackish solutions to a problem, such as replacing one character with another, performing some operations and then switching the replacement character back to the original one, look for a cleaner solution. There will always be one. Hackish solutions will not enhance your reputation among other coders and will cause you embarrassment if you must revise your code at a later date, after have gained more experience.

CodePudding user response：

You can identify the spaces outside square bracket by the following regex:

"  (?![^[\]]*\])"

Explanation:

1 or more consecutive space
negative look ahead to ensure that there is no closing square bracket before a opening square bracket
if both 1 and 2 conditions are met then the space(s) gets matched

Demo 1

You can also identify spaces inside bracket by the following regex:

"  (?=[^[\]]*\])"

1 or more consecutive space
Positive look ahead to ensure that there is a closing square bracket before a opening square bracket.
if both 1 and 2 conditions are met then the space(s) inside the boxes gets matched

Demo 2

Update:

My understanding from the original post is to make list inside list by splitting spaces inside and outside of the braces as well. Combined python code to extract your desired output ( run here )

import re
regex = r"  (?![^[\]]*\])"
test_str = "0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 [-0.01357987  0.99989218 -0.00558794] [ 0.50810066  0.81535196 -0.27755161] -18017079.1047535 10307726.258588774 -23524317.110919423 22838.17515528947 36648.54674929567 -12475.426190771163 20757272.462656207 5 5 0.005 0 5 2 0.0005 3 -98.28031520537542 29.516134353642414 19998.73252382984 -0.0055879708379507065 -0.06085533474930652 359.2218946628823 818.306543386653 2.7826806154507513 8.100054108045068 -0.7584403000503389 -0.02994106840115437 -0.0628111825224635 0.058338781314879004 242.42818865783832 0.0 0.8063781178568004 -2.6036838124274486 0.0 -0.734866228020307 -0.062 -0.062 0.008726849073962957 0.0 123.16666557966661 1.2292998660484957e-09 0.0 0.0 25619.0 Allies [-0.06088792  0.00475117  0.9981333 ] 0.5064766089927465 0.3371159370714128 0.6267890628740791 1.6191164404478644 -4.404605641298986 1.0085164509526248 0.9403428264947271 1.002228406356249 0.5911076156375097 0.04943091153402836 -0.12347543075231103 -0.031096345163790243 -0.1049357617938111 0.024866980145114622 0.04861966645392242"
list = re.split(regex,test_str)

for i in range(len(list)):
    if re.search(r'^\[',list[i]):
        tmp=re.sub(r'\[ *| *\]','',list[i])
        tmp2=re.split(regex,tmp)
        list[i]=tmp2

print(list)

output:

['0', '0', '0', '0', '0', '0', '1', '0', '0', '0', '1', '0', '0', '0', '0', ['-0.01357987', '0.99989218', '-0.00558794'], ['0.50810066', '0.81535196', '-0.27755161'], '-18017079.1047535', '10307726.258588774', '-23524317.110919423', '22838.17515528947', '36648.54674929567', '-12475.426190771163', '20757272.462656207', '5', '5', '0.005', '0', '5', '2', '0.0005', '3', '-98.28031520537542', '29.516134353642414', '19998.73252382984', '-0.0055879708379507065', '-0.06085533474930652', '359.2218946628823', '818.306543386653', '2.7826806154507513', '8.100054108045068', '-0.7584403000503389', '-0.02994106840115437', '-0.0628111825224635', '0.058338781314879004', '242.42818865783832', '0.0', '0.8063781178568004', '-2.6036838124274486', '0.0', '-0.734866228020307', '-0.062', '-0.062', '0.008726849073962957', '0.0', '123.16666557966661', '1.2292998660484957e-09', '0.0', '0.0', '25619.0', 'Allies', ['-0.06088792', '0.00475117', '0.9981333'], '0.5064766089927465', '0.3371159370714128', '0.6267890628740791', '1.6191164404478644', '-4.404605641298986', '1.0085164509526248', '0.9403428264947271', '1.002228406356249', '0.5911076156375097', '0.04943091153402836', '-0.12347543075231103', '-0.031096345163790243', '-0.1049357617938111', '0.024866980145114622', '0.04861966645392242']