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How to filter a column by the last characters in Python

Time:04-08

I have a column with a string similar to

country string_num
Botswana 864-0-0
Germany 968-0-5
Thailand 684-1-0

I would like to filter out all the strings that end with the numbers-0-0 and get a full data set view of rest.

I have tried the following code:

new_df = df[df['string_num'] > '-0-0']

The code runs, but I still see the rows that end with -0-0.

What can I change on my code that will have me seeing only the string_num that are greater than -0-0?

Thank you in advance for the assistance.

CodePudding user response:

You can use str.endswith and invert the boolean Series with ~:

new_df = df[~df['string_num'].str.endswith('-0-0')]

or using a regex ($ anchors the pattern to the end of the string):

new_df = df[~df['string_num'].str.contains('-0-0$')]

output:

    country string_num
1   Germany    968-0-5
2  Thailand    684-1-0
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