I wrote this program which displays the address of a stored array :

#include <stdio.h>

int main() {

    int n;
    scanf("%d", &n);
    int L[100];
    for (int i = 0; i < n; i  ) {
        printf("L[%d]=", i);
        scanf("%d", &L[i]);
    }
    
    printf("The address of L : %d \n", L);
    return 0;
}

I noticed that sometimes the program gives negative address which I did not quite understand.

Why there are negative addresses in memory?
Is this related to the C language?

CodePudding user response：

Why there are negative addresses in memory?

This is an unsupported concern as the output was based on broken code.

Do not use a mis-matched specifier "%d" to print addresses and incur undefined behavior (UB). "%d" is for int. Use "%p" with void *. The format of address output is implementation dependent. I have never come across an implementation that reports negative addresses.

printf("The address of L : %p\n", (void *) L);

You may get an output like

The address of L : 0xffffca70
// or 
The address of L : ffff:ca70
// or 
The address of L : Red:70

A pointer has integer like attributes, but a pointer type is not certainly reported like an integer. It is implementation defined.

Save time - enable all warnings too.