Function iisTidy(number) doesn't give the desired result-CodePudding

function isTidy(number) {

  let str = number.toString();

  for (let i = 1; i < str.length; i  ) {

    if (str.charAt(i) < str.charAt(i   1)) {
      return true;
    }
    if (str.charAt(i) > str.charAt(i   1)) {
      return false;
    }
    if (str.charAt(i) == str.charAt(i   1)) {
      return false;
    }
  }
}

console.log(isTidy(135587));

How it have to work:

isTidy(12) ==> true

The numbers { 1, 2 } are in non-decreasing sequence, i.e. 1 <= 2.

isTidy(32) ==> false

The numbers { 3, 2 } are in descending order, that is, 3 > 2.

isTidy(1024) ==> false

The numbers { 1, 0, 2, 4 } are in descending order because 0 < 1.

isTidy(3445) ==> true

The numbers { 3, 4, 4, 5 } are in non-decreasing sequence, because 4 <= 4.

isTidy(13579) ==> true

The numbers { 1, 3, 5, 7, 9} are in ascending order.

CodePudding user response：

You need to check the previous digit as well and exit early if the number are not equal or increasing.

At the end return true.

function isTidy(number) {
    let str = number.toString();
    for (let i = 1; i < str.length; i  ) {
        if (str[i - 1] > str[i]) return false;
    }
    return true;
}

console.log(isTidy(135578));
console.log(isTidy(135587));

CodePudding user response：

function isTidy(number) {
  let str = number.toString();
  for (let i = 1; i < str.length; i  ) {
    let nextNumber = str.charAt(i   1);
    if (nextNumber != "" && str.charAt(i) > nextNumber) return false;
  }
  return true;
}

console.log(isTidy(135587));