im learning Python and im trying to come up with a for loop (or any other method) that can return multiples of 100 but rounded to the nearest thousand, here's what i have right now:

huneds = [h * 100 for h in range(1,50)]
    
for r in huneds:
    if r % 3 == float:
        print(r)
    else:
        break

CodePudding user response：

The built-in round() function will accept a negative number that you can use to round to thousands:

for r in huneds:
    print(round(r, -3))

Which prints:

0
0
0
0
0
1000
1000
1000
1000
1000
1000
1000
1000
1000
2000

...

4000
4000
5000
5000
5000
5000

CodePudding user response：

You can see use

for n in range(0,2500,100):
  print(n, ' -> ',1000 * round(n / 1000))

CodePudding user response：

For any number m, m is a multiple of n if the remainder of n / m is 0. I.e. n % m == 0 or in your case; r % 100 == 0, as the modulus operator (%) returns the remainder of a division. Use:

for r in huneds:
    if r % 100 == 0:
        print(r)

But every number is already a multiple of 100, as you multiplied all of them by 100.

You may be after something like:

# Range uses (start, stop, step) params
# print(list(range(0, 200, 10))) --> [0, 10, 20, ... 170, 180, 190]

for r in range(0, 200, 10):
    if r % 100 == 0 and r != 0:
        print(r)

Outputs

100

But you would like to round to the nearest 1000. The round() function can do that.

for r in range(0, 2000, 10):
    if r % 100 == 0 and r != 0:
        print(f"{r} | {round(r, -3)}")

100 | 0
200 | 0
300 | 0
400 | 0
500 | 0
600 | 1000
700 | 1000
800 | 1000
...

• The f string does the same as r ' | ' round(r, -3)
  • This shows the number that is a multiple of 100 which is r, and then it rounded to the nearest 1000
• round()'s second argument is the amount of digits to round too, as we are going to the nearest 1000, we use -3 as you are going on the left side of the decimal

---

I suggest having a read of:

https://www.w3schools.com/python/ref_func_range.asp

And I highly reccomend: this site (python principles) for learning python. Pro membership is currently free

CodePudding user response：

Simply do this,

list(map(lambda x: round(x/1000) * 1000, huneds))

It'll return you a list of rounded values for all the items of the list huneds.