I need to get:
- If either of the characters is not a letter, return -1
- If both characters are the same case, return 1
- If both characters are letters, but not the same case, return 0
Examples:
'a' and 'g' returns 1
'A' and 'C' returns 1
'b' and 'G' returns 0
'B' and 'g' returns 0
'0' and '?' returns -1
Now my code is uncorrect:
function sameCase(a, b) {
if (a.match(/a-z/) && b.match(/a-z/)) {
return 1;
}
if (a.match(/A-Z/) && b.match(/A-Z/)) {
return 0;
}
if (b.match(/a-z/) && a.match(/A-Z/)) {
return 0;
}
return -1;
}
console.log(sameCase('a', 'b'));
console.log(sameCase('A', 'B'));
console.log(sameCase('a', 'B'));
console.log(sameCase('B', 'g'));
console.log(sameCase('0', '?'));
Help, please..
CodePudding user response:
You are using regex incorrectly. You should have used /[a-z]/
if you want to check that your character is a letter from a to z.
function sameCase(a, b){
if (a.match(/[a-z]/) && b.match(/[a-z]/)) {
return 1;
}
if (a.match(/[A-Z]/) && b.match(/[A-Z]/)) {
return 1;
}
if (b.match(/[a-z]/) && a.match(/[A-Z]/)) {
return 0;
}
if (a.match(/[a-z]/) && b.match(/[A-Z]/)) {
return 0;
}
return -1;
}
console.log(sameCase('a', 'b'));
console.log(sameCase('A', 'B'));
console.log(sameCase('a', 'B'));
console.log(sameCase('B', 'g'));
console.log(sameCase('0', '?'));
CodePudding user response:
You are using the wrong syntax for the regular expressions.
/a-z/
matches the string a-z
. If you want to test for a range of characters, you need to wrap the range in []
.
Also your return values didn't match the expectations you described.
function sameCase(a, b) {
if (
(a.match(/[a-z]/) && b.match(/[a-z]/)) ||
(a.match(/[A-Z]/) && b.match(/[A-Z]/))
) {
return 1;
}
if (
(b.match(/[a-z]/) && a.match(/[A-Z]/)) ||
(b.match(/[A-Z]/) && a.match(/[a-z]/))
) {
return 0;
}
return -1;
}
console.log(sameCase('a', 'b'));
console.log(sameCase('A', 'B'));
console.log(sameCase('a', 'B'));
console.log(sameCase('B', 'g'));
console.log(sameCase('0', '?'));
CodePudding user response:
Presented below is one possible way to achieve the desired objective.
Code Snippet
// helper methods to determin lower, upper cases
const isLower = x => x === x.toLowerCase();
const isUpper = x => x === x.toUpperCase();
const sameCase = (a, b) => {
// if either "a" or "b" are not "letter"s, return -1
if (!a.match(/[a-z|A-Z]/) || !b.match(/[a-z|A-Z]/)) return -1;
// if both "a" and "b" are either lower or upper case, return 1
if ((isLower(a) && isLower(b)) || (isUpper(a) && isUpper(b))) return 1;
// return 0 (since "a", "b" are letters, but not same case)
return 0;
};
console.log("sameCase('a', 'b'): ", sameCase('a', 'b'));
console.log("sameCase('A', 'B'): ", sameCase('A', 'B'));
console.log("sameCase('a', 'B'): ", sameCase('a', 'B'));
console.log("sameCase('B', 'g'): ", sameCase('B', 'g'));
console.log("sameCase('0', '?'): ", sameCase('0', '?'));
.as-console-wrapper { max-height: 100% !important; top: 0 }
Explanation
Inline comments added to the snippet above.
CodePudding user response:
Just as additional information
Building on top of connexo's approach and turning it into a solution which does not just cover the basic latin upper- and lower-case letters, one could replace each character class with its unicode property escapes counterpart which in addition covers each a much wider range of characters ...
// based on basic latin letter character classes.
function sameCaseBasicLatin(a, b) {
if (
(a.match(/[a-z]/) && b.match(/[a-z]/)) ||
(a.match(/[A-Z]/) && b.match(/[A-Z]/))
) {
return 1;
}
if (
(b.match(/[a-z]/) && a.match(/[A-Z]/)) ||
(b.match(/[A-Z]/) && a.match(/[a-z]/))
) {
return 0;
}
return -1;
}
// ... ok ...
console.log('`sameCaseBasicLatin` invoked with basic latin letters');
console.log(sameCaseBasicLatin('a', 'b'));
console.log(sameCaseBasicLatin('A', 'B'));
console.log(sameCaseBasicLatin('a', 'B'));
console.log(sameCaseBasicLatin('B', 'g'));
console.log(sameCaseBasicLatin('0', '?'));
// ... but ... not ok.
console.log('`sameCaseBasicLatin` invoked with diacritic latin letters');
console.log(sameCaseBasicLatin('â', 'ê'));
console.log(sameCaseBasicLatin('Â', 'Ê'));
console.log(sameCaseBasicLatin('â', 'Î'));
console.log(sameCaseBasicLatin('Ô', 'ä'));
console.log(sameCaseBasicLatin('-', '#'));
// make use of unicode property escapes.
function sameCaseLetters(a, b) {
// lowercase letter as unicode property escape.
const regXLowerCaseLetter = (/\p{Ll}/u);
// uppercase letter as unicode property escape.
const regXUpperCaseLetter = (/\p{Lu}/u);
if (
(regXLowerCaseLetter.test(a) && regXLowerCaseLetter.test(b)) ||
(regXUpperCaseLetter.test(a) && regXUpperCaseLetter.test(b))
) {
return 1;
}
if (
(regXLowerCaseLetter.test(a) && regXUpperCaseLetter.test(b)) ||
(regXUpperCaseLetter.test(a) && regXLowerCaseLetter.test(b))
) {
return 0;
}
return -1;
}
// ... ok ...
console.log('`sameCaseLetters` invoked with basic latin letters');
console.log(sameCaseLetters('a', 'b'));
console.log(sameCaseLetters('A', 'B'));
console.log(sameCaseLetters('a', 'B'));
console.log(sameCaseLetters('B', 'g'));
console.log(sameCaseLetters('0', '?'));
// ... and ... also ok.
console.log('`sameCaseLetters` invoked with diacritic latin letters');
console.log(sameCaseLetters('â', 'ê'));
console.log(sameCaseLetters('Â', 'Ê'));
console.log(sameCaseLetters('â', 'Î'));
console.log(sameCaseLetters('Ô', 'ä'));
console.log(sameCaseLetters('-', '#'));
.as-console-wrapper { min-height: 100%!important; top: 0; }
CodePudding user response:
Change your if condition and check upper/lower case.change 2nd number if condition return 0 to 1 (if (a.charAt(/A-Z/) && b.charAt(/A-Z/)) { return 0; }). and check non alphabetic value for -1. try below code.
function sameCase(a, b){
if(a.match(/[a-z]/i) && b.match(/[a-z]/i)) {
if (a.toLowerCase() === a && b.toLowerCase() === b) {
return 1;
}
if (a.toUpperCase() === a && b.toUpperCase() === b) {
return 1;
}
if (b.toLowerCase() === b && a.toUpperCase() === a || a.toLowerCase() === a && b.toUpperCase() === b) {
return 0;
}
}else{
return -1;
}
}
console.log(sameCase('a', 'b'));
console.log(sameCase('A', 'B'));
console.log(sameCase('a', 'B'));
console.log(sameCase('B', 'g'));
console.log(sameCase('0', '?'));