I am trying to count the number of digits for each string in list of strings:

['', '', '000000000100111101', '', '', '0000112112111101011100000000001', '', '', '', '', '',]

So the expected output I would like to get is

[0 0 18 0 0 31 0 0 0 0 0]

I was thinking about using numpy count but the data type for list of strings is list so should I be using len?

I would greatly appreciate anyone's help thank you.

CodePudding user response：

Use a list comprehension along with the len() function:

inp = ['', '', '000000000100111101', '', '', '0000112112111101011100000000001', '', '', '', '', '',]
lengths = [len(x) for x in inp]
print(lengths)  # [0, 0, 18, 0, 0, 31, 0, 0, 0, 0, 0]

CodePudding user response：

Use the map function to apply the built in len function to each number in the list, and then convert the map object to a list.

nums = ['', '', '000000000100111101', '', '', '0000112112111101011100000000001', '', '', '', '', '',]
lengths = list(map(len, nums))
print(lengths)

Output:

[0 0 18 0 0 31 0 0 0 0 0]

CodePudding user response：

The get that exact output you could do this:

L = ['', '', '000000000100111101', '', '', '0000112112111101011100000000001', '', '', '', '', '',]

print(f'[{" ".join(map(str, map(len, L)))}]')

Output:

[0 0 18 0 0 31 0 0 0 0 0]

CodePudding user response：

Use len() function along with for loop to get the count for each string inside a list. like this

newList = []
for value in values:

    newList.append(len(value))

Output:

[0, 0, 18, 0, 0, 31, 0, 0, 0, 0, 0]

If you want the output without comma, you want to add a little statements like this!

anotherList = []
for value in values:

    try:
        if anotherList[0] != "":
            anotherList[0] = str(anotherList[0])   " "   str(len(value))

    except IndexError:
        anotherList.append(len(value))

Output:

['0 0 18 0 0 31 0 0 0 0 0']