How to only combine elements of lists that dont give 0 when multiplied with each other-CodePudding

I would like to only combine elements of lists that dont give 0 when multiplied with each other.

a = [1, 2, 3, 4, 5]
b = [10, 20, 30, 40, 50]
c = [0, 0, 3, 0, 5]

Since 1x10x0 = 0, 2x20x0 = 0, 3x30x3 = 270, 4x40x0 = 0, 5x50x5 = 1250

only combine

a = [3, 5]
b = [30, 50]
c = [3, 5]

expected output:

d = [(3,30,3), (5,50,5)]

CodePudding user response：

list = []

for i in range(len(a)):
    if 0 in [a[i], b[i], c[i]]:
        continue
    else:
        list.append((a[i], b[i], c[i]))

print(list)

CodePudding user response：

You can do something like

a = [1, 2, 3, 4, 5]
b = [10, 20, 30, 40, 50]
c = [0, 0, 3, 0, 5]
final_ouput=[(x,y,z) for x,y,z in zip(a,b,c) if x * y* z !=0]

Output

[(3, 30, 3), (5, 50, 5)]

CodePudding user response：

Use zip to iterate the lists in parallel.

As you deal with integers, you could use all to identify if you have any zero (in which case the product will be 0):

a = [1, 2, 3, 4, 5]
b = [10, 20, 30, 40, 50]
c = [0, 0, 3, 0, 5]

d = [x for x in zip(a,b,c) if all(x)]

output: [(3, 30, 3), (5, 50, 5)]

How it works:

all will check if all values in an iterable are truthy. For integers, 0 is the only non truthy value. So all(list_of_integers) is False if any value is 0, and True otherwise.

Alternative syntax:

An alternative syntax could be to use filter:

d = list(filter(all, zip(a, b, c)))