I have a DB like this:

a <-c(4, 2, 10, 2, 10, 6, 2)
b <-c(4, 6, 70, 8, 18, 4, 3)
rbind(a,b)

I can create something like this:

x <- (4, 4, 2, 6, 10, 70, 2, 8, 10, 18, 6, 4, 3)

A DB that contains a and b order in this way, it is possible? I need to do a time series and the value must be in the same position

CodePudding user response：

rbind works only when both the vectors are of the same length or else it will give unexpected output. i.e.

> rbind(c(4, 3, 5), c(3, 4))
     [,1] [,2] [,3]
[1,]    4    3    5
[2,]    3    4    3
Warning message:
In rbind(c(4, 3, 5), c(3, 4)) :
  number of columns of result is not a multiple of vector length (arg 2)

and when we do c to make a vector, it returns an extra 3 from recycling

A more general approach is to order based on the sequence of values in both vector while concatenating the vectors`

c(a, b)[order(c(seq_along(a), seq_along(b)))]
[1]  4  4  2  6 10 70  2  8 10 18  6  4  2  3