Removing line breaks between 2 different character sequences-CodePudding

I'm editing a csv file which contains hidden line breaks. When I apply the following php script, the line breaks are successfully removed from the entire file.

$csvFileNew = str_replace(array("\r", "\n"), '', $csvFileOld);

But I only want to remove these line breaks from within certain sections of the file - between all occurrences of the following (enclosed in single quotes):

$start = ',""';
$end = '",';

My current script looks like this:

$csvFileOld = "pre text appears here....,\"\"key words appear here\"\",....post text appears here";
//line break always appears between the final 2 quotation marks

$csvFileNew = preg_replace_callback('`,""([^"]*)",`', function($matches)
    {
        return str_replace(array("\r", "\n"), '', $matches[1]);

    },$csvFileOld);

Unfortunately, this script doesn't remove the line break - I'm assuming the regex I've used doesn't grab enough. Can anyone suggest an elegant solution?

I know it won't be possible for answers to include a working example because of the line break, however I'm really just after a solution which grabs the correct content between the delimiters.

CodePudding user response：

Your can use

<?php

$csvFileOld = "pre text appears here....,\"\"key\n\n words\r\n appear\r\n here\"\",....post text appears here";
//line break always appears between the final 2 quotation marks

$csvFileNew = preg_replace_callback('`,""(.*?)",`s', function($matches)
{
    return str_replace(array("\r", "\n"), '', $matches[1]);
},$csvFileOld);
echo $csvFileNew;

See the PHP demo.

The ,""(.*?)", regex now matches from ,"" till the first occurrence of ", substring.

The s flag is added to allow dots to match across lines.