I am attempting to rename files found in a main folder, but then put the renamed files in the same directory as the files to be copied. This is my original folder structure:
Main Folder
|
|____file1.txt
|____file2.txt
|____file1.txt
I want to now create a folder under the Main Folder called "Renamed" and place the renamed files in there. The new folder structure should look like this after successfully executing the code:
Main Folder
|
|____Renamed
| |
| |____renamed-file1.txt
| |____renamed-file2.txt
| |____renamed-file3.txt
|
|____file1.txt
|____file2.txt
|____file1.txt
However, in the code that I have so far, I cannot create the "Renamed" folder under the Main Folder as I get the error message Run-time error '5': Invalid procedure call or argument
that seem to occur at the line fso.CopyFolder sItem, strPath2
. Can you help me create the folder structure with the renamed folder and files.
Here is my code:
Sub RenameFile()
Dim fldr As FileDialog
Dim sItem As String
Dim strPath As String
Dim strPath1 As String
Dim strPath2 As String
Dim fso
Set fso = CreateObject("Scripting.FileSystemObject")
Set fldr = Application.FileDialog(msoFileDialogFolderPicker)
Dim z As String
Dim s As String
Dim V As Integer
Dim TotalRow As Integer
With fldr
.Title = "Select a Folder"
.AllowMultiSelect = False
.InitialFileName = Application.DefaultFilePath
If .Show <> -1 Then GoTo NextCode
sItem = .SelectedItems(1)
End With
TotalRow = ActiveSheet.UsedRange.Rows.Count
NextCode:
strPath = sItem
strPath2 = fso.BuildPath(sItem, "Renamed")
' Create the folder "Renamed"
fso.CopyFolder sItem, strPath2
For V = 1 To TotalRow
' Get value of each row in columns 1 start at row 2
z = Cells(V 1, 1).Value
' Get value of each row in columns 2 start at row 2
s = Cells(V 1, 2).Value
Dim sOldPathName As String
sOldPathName = fso.BuildPath(strPath2, z)
sNewPathName = fso.BuildPath(strPath2, s)
Name sOldPathName As sNewPathName
On Error Resume Next
Name sOldPathName As s
Next V
MsgBox "Congratulations! You have successfully renamed all the files"
End Sub
CodePudding user response:
Copy and Rename Files Using Dir
and FileCopy
- Using FileCopy is much faster, simpler, and more straightforward: it copies and renames in one go.
- This is a simplified example to get you familiar with
Dir
andFileCopy
. In your case, you would 'Dir' each name in columnA
and if the length of the filename is greater than 0 (confirming that the file exists), you would 'FileCopy the source path to the destination path (using the names in columnB
)'.
Sub RenameFiles()
' Source
Const sFilePattern As String = "*.*"
Dim sInitPath As String: sInitPath = Application.DefaultFilePath & "\"
' Destination
Const dSubFolderName As String = "Renamed"
Const dPrefix As String = "renamed-"
Dim sFolderPath As String
With Application.FileDialog(msoFileDialogFolderPicker)
.Title = "Select a Folder"
.InitialFileName = sInitPath
If .Show <> -1 Then
MsgBox "You canceled.", vbExclamation
Exit Sub
End If
sFolderPath = .SelectedItems(1) & "\"
End With
Dim dFolderPath As String: dFolderPath = sFolderPath & dSubFolderName & "\"
If Len(Dir(dFolderPath, vbDirectory)) = 0 Then MkDir dFolderPath
Dim sFileName As String: sFileName = Dir(sFolderPath & sFilePattern)
If Len(sFileName) = 0 Then
MsgBox "No files found.", vbExclamation
Exit Sub
End If
On Error GoTo FileCopyError
Do Until Len(sFileName) = 0
FileCopy sFolderPath & sFileName, dFolderPath & dPrefix & sFileName
sFileName = Dir
Loop
On Error GoTo 0
MsgBox "Congratulations! You have successfully renamed all the files.", _
vbInformation
Exit Sub
FileCopyError:
Debug.Print "Run-time error '" & Err.Number & "': " & Err.Description _
& vbLf & "Could not copy '" & sFileName & "'."
Resume Next
End Sub