I have a list of words. I figgured out how to count the occurrence of each word. I now want to know how many words appear how many times(?) in that list. The output should look something like this:

4.500 Words appeard 1 time

6.000 Words appeard 2 time ...

Example:

list = ["hello", "time", "burger", "hello", "mouse", "time", "time"]

Expected output:

3 Word occurred 1 time
1 Word orrcured 2 time
1 Word occurred 3 time

I hope it is clear what I mean to do. I cant share code really since I have no clue how to do it.

Is there an inbuilt function with Counter or Pandas that can do this?

Or does anyone have a smooth way of computing this ?

THANKS A LOT !

CodePudding user response：

Yes; use a Counter to count the number of times each word appears, and then use a Counter on that counter to count how many words appear each number of times.

>>> words = ["hello", "time", "burger", "hello", "mouse", "time", "time"]
>>> from collections import Counter
>>> word_counts = Counter(words)
>>> count_counts = Counter(word_counts.values())
>>> for times, words in count_counts.items():
...     print(f"{words} words occurred {times} times")
...
1 words occurred 2 times
1 words occurred 3 times
2 words occurred 1 times

Note that word_counts gives the counts per word, and then count_counts gives the counts per count in word_counts:

>>> word_counts
Counter({'time': 3, 'hello': 2, 'burger': 1, 'mouse': 1})
>>> count_counts
Counter({1: 2, 2: 1, 3: 1})

CodePudding user response：

If you know how to count the occurrences of each word, the procedure is straightforward. In pseudo-code:

1. Let A = n*[0], where n is the amount of words
2. For each word, let m be the number of times the word occurs. Then do A[m]
3. For i in range n, print(str(A[i]) " words appear " str(i) "times")