how to get img src url to python?-CodePudding

I want to get the following scr url.

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from datetime import date
import openpyxl
import time

from webdriver_manager.chrome import ChromeDriverManager
driver = webdriver.Chrome(ChromeDriverManager().install())

img_class = 'thumbnail_thumb_wrap__1pEkS _wrapper' #div
img_xpath = '/html/body/div/div/div[2]/div[2]/div[3]/div[1]/ul/div/div[1]/li/div/div[1]/div/a/img'
img_css = '.thumbnail_thumb_wrap__1pEkS .thumbnail_thumb__3Agq6:before'

item_img = driver.find_elements(By.XPATH, img_xpath).__getattribute__('src')

print(item_img)

I searched by Xpath, css_select, and class_name, but I see an error message that none of them have 'src'. What am I missing here?

CodePudding user response：

I believe you have to use the .get_attribute("src") method, instead of the __getattribute__ method. The former is implemented by Selenium as a method to get an attribute from the webpage, while the latter is a builtin Python method to try and get the attribute of the Python object.

See here for the Selenium get_attribute documentation, and here for the Python __getattribute__ method that you should not use in this situation.

Example

from selenium import webdriver
from selenium.webdriver.common.by import By

driver = webdriver.Chrome()

img_xpath = '/html/body/div[4]/main/div[1]/div[1]/div[1]/div/div/div[2]/div/div/img'
driver.get("https://github.com")
item_web_element = driver.find_element(By.XPATH, img_xpath)
item_img = item_web_element.get_attribute("src")
print("The source is:", item_img)

driver.quit()