Suppose I have these documents:

[
    {
        _id: 132143124,
        orders: [true, false, false],
    },
    {
        _id: 3123,
        orders: [true, true, true],
    },
];

How do I get only the documents that dont have 'false' in their orders array. I need an aggregate stage solution. ( MongoDB aggregate solution )

CodePudding user response：

You can use $not or $ne ( as Mongo's query language flattens arrays ) for this, like so:

db.collection.find({
  orders: {$ne: false}
})

Mongo Playground

same syntax will work in the aggregation pipeline: Mongo Playground Aggregation

CodePudding user response：

You could use filter function for arrays:

    const results = [
      {
        _id: 1,
        orders: [true, false, false],
      },
      {
        _id: 2,
        orders: [true, true, true],
      }
    ]
    
    const filtered_results = results.map(({orders, ...data}) => {
       return {
         orders: orders.filter((order)=>order === true), 
         ...data
        }
    })
    
    console.log(filtered_results)