Regular expression to match word followed by a pair of brackets-CodePudding

I have a string which is:

str2s = 'orange,juices,apple,apple[-2]'

I'm trying to extract all those words as long as the bracket out, so I want:

'orange', 'juices', 'apple', 'apple[-2]'

I tried using:

re.findall(
    '[A-Za-z][A-Za-z0-9_%\\.]{0,}\[?[a-zA-Z0-9_]*\]?',
    str2s,
    flags=re.IGNORECASE
)

But it only returned:

'orange', 'juices', 'apple', 'apple['

How to get the -2] as well?

CodePudding user response：

In order to split an string to a list I think you have to know the exact separator, or being able to identify those separators, being it , or [,.] or others.

If you can't define separators from items, I think it will be very hard to achieve your goal via common methods.

With that being said, in your case of orange,juices,apple,apple[-2], you may use r'([\w\[\]\-] )' https://regex101.com/r/2Xj7AR/1

CodePudding user response：

The following code will extract the words the way you want:

import re

words = re.compile(r'\w \[?-?\d*\]?', re.IGNORECASE)
s = 'orange,juices,apple,apple[-2],pineapple[20]'

words.findall(s)

Which will result in the following:

['orange', 'juices', 'apple', 'apple[-2]', 'pineapple[20]']

Bear in mind that the snippet above was written with the example string you provided as the base. If you need to match other types of words (007