How to print matched regex pattern using awk svr08-core1-1654761552.278?-CodePudding

How to print matched regex pattern using awk?

How to print svr08-core1-1654761552.278 columns?

My log files

"/usr/local/bin/publisher calllog -account='IE-00683' -uniqueid='svr08-core1-1654762416.510' -linkedid='svr08-core1-1654762416.510' -channel='SIP/IE-00683-72-000001f8' -sipcallid='3382826129@192_168_2_61' -originalsipcallid='3382826129@192_168_2_61' -src_ext='72' -dst_ext='44' -call_direction='internal' >>/var/log/asterisk/publisher_asterisk.log 2>&1 &") in new stack

CodePudding user response：

How to print matched regex pattern using awk?

match function sets RSTART to start of match or 0 if not match found and RLENGTH to length of match or -1 if not match found. RSTART value is also return value. Variables set can be used with substr to get matched string, consider following simple example, let file.txt content be

abc 123 def
7 ghi 8
nodigitshere

then

awk 'match($0,/[0-9] /){print substr($0, RSTART, RLENGTH)}' file.txt

gives output

123
7

Explanation: match function is used, return of which is true if match found and false otherwise, when considering as boolean. I instruct GNU AWK to look for 1 or more ( ) digits ([0-9]) in whole line ($0). If there is match I print substring of whole line ($0) starting at start of match and of length of match. Note that if line contain more 1 substring matching regex leftmost one (first) will be printed as seen in 2nd line.

(tested in gawk 4.2.1)

CodePudding user response：

I have a log file and I want to extract the following pattern from the log file.

I just want to get the following pattern.

svr08-core1-1654762440.516

[2022-06-09 09:14:00] VERBOSE[24148][C-000000e4] pbx.c: [2022-06-09 09:14:00] -- Executing [s@macro-internalcall:207] System("SIP/IE-00730-10-000001fe", "/usr/local/bin/publisher calllog -account='IE-00730' -uniqueid='svr08-core1-1654762440.516' -linkedid='svr08-core1-1654762440.516' -channel='SIP/IE-00730-10-000001fe' -sipcallid='[email protected]' -originalsipcallid='[email protected]' -src_ext='10' -dst_ext='22' -call_direction='internal' >>/var/log/asterisk/publisher_asterisk.log 2>&1 &") in new stack

CodePudding user response：

Here is a potential solution with sed:

sed -n "s/.*\-uniqueid='\([[:alnum:]\.-]\{1,\}\)'.*/\1/p" file.log

If this doesn't solve your problem, please edit your question to include more details and/or example input and the corresponding expected output.