Using array of object create a new array that contains all the objects from the original array of ob-CodePudding

help please, i have this array of object and must to create a new array that contains all the objects from the original array of object that have a numerical value greater than 15. how can i do this ? which method a must to use ?

const names = [
  { name: 'Anna' },
  { num: 27 },
  { name: 'Valeria', age: 20},
  { secondname: 'Wilson' },
  { age: 12, name: 'Max' },
  { weight:'50kg', height: '172cm', name: 'Nick' }
]

i try to use filter,but it should see any field that has a number value not just age or num

const number = arr.filter(a => a.num || a.age > 15);
console.log(number);

CodePudding user response：

If you like to get only numbers, you chould check the values of the object with Array#some and typeof operator.

const
    names = [{ name: 'Anna' }, { num: 27 }, { name: 'Valeria', age: 20 }, { secondname: 'Wilson' }, { age: 12, name: 'Max' }, { weight: '50kg', height: '172cm', name: 'Nick' }],
    result = names.filter(o => Object
        .values(o)
        .some(v => typeof v === 'number' && v > 15)
    );

console.log(result);

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