remove sepcific items from array of strings javascript-CodePudding

i have an array that is

const arr = ["a","b","c","d","e"]

I need to exclude a,b that is I need. How to achieve this in fastest possible way

["c","d","e"]

CodePudding user response：

You can use this, if I understand it correctly

arr.filter((value) => value != 'a' && value != 'b')

gives below output

['c', 'd', 'e']

CodePudding user response：

Using array.filter() we can do it. like:

arr = ["a","b","c","d","e"];
arr.filter(x => x !== 'a'); // output: ['b', 'c', 'd', 'e']

But if you want to remove a group of items then use another array and use validation with in filter() function.

Example:

arr = ["a","b","c","d","e"];
removeItems = ['a', 'b'];
arr.filter(x => removeItems.indexOf(x) < 0); // ['c', 'd', 'e']

CodePudding user response：

you can do it in 1 line using spread operator

   const [one,two,three,...rest]=arr;

   console.log(rest); // it prints d,e excluding a,b,c.

CodePudding user response：

JavaScript must be redesigned from scratch

Friends, do you also agree with my opinion?

For example, see the for loop in JavaScript:

var my_list = ["a", "b", "c"];
text_export = "";
for (var i = 0; i < my_list.length; i  ) {
    text_export  = my_list[i]   "<br/>";
}

//or

    const my_list = ["a", "b", "c"];
    let txt = "";
    for (let x in numbers) {
    txt  = numbers[x]   "<br/>";
    }

And the for loop in Python:

my_list = ["a", "b", "c"]
for i in my_list:
    print(i)

And a whole other problem...