If I have this structure:

 const datesList = [2022-07-15T19:41:12.620Z, 2022-07-20T11:21:52.596Z, 2022-07-13T11:21:50.596Z]

How can I loop through it and find out which one is the later and the earlier date?

I've tried using forEach loop and its not working..

CodePudding user response：

You can compare using getTime() which gets the time in ms since 1970

var dateList = [new Date(Date.parse("2022-07-15T19:41:12.620Z")), new Date(), new Date( 5), new Date(1236876666273)]

console.log(dateList.sort(function(a, b) {
  if (a.getTime() < b.getTime()) {
    return -1
  }
  if (a.getTime() > b.getTime()) {
    return 1
  }
  return 0
}))

CodePudding user response：

• Date.parse() returns the number of milliseconds since January 1, 1970, 00:00:00 UTC of string input for valie date.
• I just used dort function of es6.

const datesList = ["2022-07-15T19:41:12.620Z", "2022-07-20T11:21:52.596Z", "2022-07-13T11:21:50.596Z"];
console.log(datesList.sort((a, b) => Date.parse(a) - Date.parse(b)));

CodePudding user response：

1. Get each string date, abd parse them into timestamp numbers

   .map(d => Date.parse(d))
   

2. Sort the array of timestamp numbers

   .sort((a, b) => a - b)
   

3. Convert the numbers into date strings

   .map(t => new Date(t));
   

const dates = ['2022-07-15T19:41:12.620Z', '2022-07-20T11:21:52.596Z', '2022-07-13T11:21:50.596Z'];
 
 let output = dates
 .map(d => Date.parse(d))
 .sort((a, b) => a - b)
 .map(t => new Date(t));
 
console.log(output);