Union of two-dimensional arrays by value-CodePudding

Good afternoon. I'm new and just learning. Please help me to solve the problem with array merging. i hav 2 arrays

let arr1 = [['boss',, 'boss I.V.', '5552654','card 100'],
            ['ard',, 'ard J.B.', '3722654','card 520'],
            ['Jon',, 'Jon sviss', '394554','card 22120'],
            ['Elty B',, 'Elty Bitry B.', '12265664', 'card 9990'],
            ['Elty B.I',, 'Elty Bitry I.','3322654', 'card 002200']];

let arr2 = [['boss', 3000, 'comm1'],
            ['Elty B', 8000.500, 'comm2']];
//-------------------------------------------- 
         //I need to get:

let arrR = [[1,'boss I.V.', '5552654', 'card 100', 3000, 'comm1'],
            [2,'Elty Bitry B.', '12265664', 'card 9990', 8000.500, 'comm2']];
//--------------------------------------------
          // i made it a loop 'for':

  arr1 = arr1.filter( (item) => arr2.find((el) => el[0] === item[0])).sort();
  for (var i = 0; i<arr1.length; i  ) {                    
    arr1[i].push(arr2[i][1],arr2[i][2]);
    arr1[i].splice(0,1);
    arr1[i][0] = i 1;
  }
  return arr1;
//--------------------------------------------
           //it is not right (((

how to do it correctly by finding by value: " if (arr1[i][0] === arr2[k][0]) " and don't use a loop?

CodePudding user response：

const arrR = arr2.map((e, i, a) => {
  const ra = arr1.find(item => item[0] === e[0]);
  return [i   1, ...ra.splice(2), ...e.splice(1)];
});

Since the resulting array has the same number of entries as arr2 I am calling map on arr2.

CodePudding user response：

you have to add commas in your arr1 statement and add the bracket at the end of the arr2 statement and remove the sort() function.