Does the constructor of a class or struct initialize the fields to their default values or not?-CodePudding

class aa{

    public int j=8;
    int f;

    public aa() {
        f=99;
    }

}

struct  bb {

    public int v = 7;
    int l;

    public bb() {
        l = 88;
    }

}

I am kind of confused as I am learning about the structs.

let's say if I create an instance of class aa, is the field j initialized to 8 which is NOT done by the constructor ? and field f is first defaulted to 0, again NOT by the constructor and then initialized to 99 in a constructor

And let's say if I create an instance of struct bb, is the v initialized to 7 which is NOT done by the constructor? And field l is FIRST defaulted to 0 NOT but the constructor? And then initialized to 88 by the constructor

CodePudding user response：

The Structure types (C# reference) documentation page describes how structs are initialized. Note that the behavior has changed a bit in recent versions of the language. In C# 11, the compiler ensures that any fields that you do not initialize, either in the constructor or in the field declaration, are assigned their default values.

Also, the Fields (C# Programming Guide) documentation page describes how fields in general are initialized:

A field can be given an initial value by using the assignment operator when the field is declared.

And also:

Fields are initialized immediately before the constructor for the object instance is called. If the constructor assigns the value of a field, it will overwrite any value given during field declaration.

If your concern is a performance one around fields being initialized twice i.e. once with their initial value assigned as part of their declaration and once in the constructor, then I'd expect the compiler to be smart enough to optimize away any redundant assignments