I'm writing a special print function that produces a cstdio printf - statement at compile time. The idea is basically that you invoke a function special_print()
with a variadic parameter list and the function will assemble the necessary printf - statement at compile time. Here's what I've got:
#include <cstdio>
#include <string_view>
// how to implement "expand" from below?
template <typename... Ts>
constexpr const char* cxpr_format = /* ... this one I've already figured out */
template <typename... Ts>
void special_print(Ts... arg)
{
printf(cxpr_format<Ts...>, expand(arg)...);
// should expand to printf("%.*s%d", string_view.size(), string_view.data(), int) with below function call
}
int main()
{
std::string_view strview = "hello world";
int integer = 2;
special_print(strview, integer);
}
I've already figured out the part for creating my format string - that one is out of the question. But now comes the problem: In case when I've got a string_view
passed in as an argument, I would need to conditionally expand it to two arguments to printf: one for the initial char pointer and one for the size which goes together with the %.*s format specifier. And this is the real crux. Can this be done somehow in C (at compile time)?
Note: Before any further questions arise I would like to point out that I have no idea on how to do this in C and this is my question. Every approach will be gladly taken into account!
CodePudding user response:
My initial thought is to forward each arg through a tuple, and then "varags apply" in the call.
template <typename T>
auto expand(T&& t) { return std::forward_as_tuple<T>(t); }
auto expand(std::string_view s) { return std::tuple<int, const char *>(s.size(), s.data()); }
template <typename... Ts>
void special_print(Ts... arg)
{
using expanded = decltype(std::tuple_cat(expand(arg)...));
[]<std::size_t... Is>(auto tup, std::index_sequence<Is...>)
{
printf(cxpr_format<Ts...>, std::forward<std::tuple_element_t<Is, expanded>>(std::get<Is>(tup))...);
}(std::tuple_cat(expand(arg)...), std::make_index_sequence<std::tuple_size_v<expanded>>{});
// should expand to printf("%.*s%d", string_view.size(), string_view.data(), int) with below function call
}
CodePudding user response:
Rather than use printf
, which only knows about types shared with C, you can use the std::format
library.
struct putchar_iterator {
using iterator_category = std::output_iterator_tag;
using value_type = void;
using difference_type = std::ptrdiff_t;
using pointer = void;
using reference = void;
putchar_iterator& operator=(char c) {
eof = (putchar(c) == EOF);
return *this;
}
constexpr putchar_iterator& operator*() { return *this; }
constexpr putchar_iterator& operator () { return *this; }
constexpr putchar_iterator& operator (int) { return *this; }
friend bool operator==(putchar_iterator lhs, std::default_sentinel_t) { return lhs.eof; }
private:
bool eof = false;
};
template <typename... Ts>
void special_print(Ts... arg)
{
// You might be able to std::format_to, but I'm not sure
std::vformat_to(putchar_iterator{}, cxpr_format<Ts...>, std::make_format_args(arg...));
}