I am looking for a way to create a mixed list in Python like this

List A = [(7-12), (18-23), 45, 67, 43]
List B = [(15-17), 67]

Is there also a function in which I could check if List B fits inside List A? and if it doesn't fit, print out the elements that didn't fit in the list?

Any help would be appreciated. Thanks!

CodePudding user response：

With pandas you can use an IntervalIndex, then compare the pairs:

listA = [(7,12), (18,23), 45, 67, 43]
listB = [(15,17), 67]

A = pd.IntervalIndex.from_tuples([x if isinstance(x, tuple) else (x,x)
                                  for x in listA])
# IntervalIndex([(7, 12], (18, 23], (45, 45], (67, 67], (43, 43]],
#               dtype='interval[int64, right]')

B = pd.IntervalIndex.from_tuples([x if isinstance(x, tuple) else (x,x)
                                  for x in listB])
# IntervalIndex([(15, 17], (67, 67]], dtype='interval[int64, right]')

out = all(any(b<=a for a in A) for b in B)

output: True

CodePudding user response：

It's a bit unclear what you mean by discrete and continuous. Do you want the open interval (7, 12) ?

Regarding the second question. Yes there is :)

I would turn the list into sets and compare them and convert them back into lists if necessary. Se the link for to see the set operations.

https://www.geeksforgeeks.org/python-set-operations-union-intersection-difference-symmetric-difference/

Hope it'll helps