Selenium with Python 3 - How to click on element-CodePudding

I am new to Selenium I have been following the documentations but they seem outdated.

(for curious people, that is the admin section of Atlassian's Cloud

What am I doing wrong? Note that I am using Edge webdriver if that matters.

Thanks.

EDIT: From first investigations, it seems that the the <label> is overlapping the input. If I indeed click on the label itself it does toggle the button. In the page code above, I tested my code on the xpath driver.find_element(By.XPATH, "//label[@data-checked='true']").click() but the thing is that there are several labels on the page that show a data-checked='true' property. How to craft the xpath so that I select the label associated with that specific input. Basically mixing the "//label[@data-checked='true']" and //input[@value='123456789abcde'] xpaths.

CodePudding user response：

Since we have no access to that page we can only guess.
So, instead of driver.find_element(By.XPATH, "//input[@value='123456789abcde']").click() Try adding a wait. The WebdriverWait is the preferred way to do that, as following:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

wait = WebDriverWait(driver, 20)

wait.until(EC.element_to_be_clickable((By.XPATH, "//input[@value='123456789abcde']"))).click()

UPD
In case you need to click the label element which is a direct parent of this input the locator can be updated as following:

wait.until(EC.element_to_be_clickable((By.XPATH, "//input[@value='123456789abcde']/.."))).click()

Another way to precisely locate that label is to find the parent div based on the child input and from it to get the child label as following:

wait.until(EC.element_to_be_clickable((By.XPATH, "//div[.//input[@value='123456789abcde']]//label"))).click()