I have been looking at a lot of questions but none of them answered my problem.

I am trying to identify vanity/special mobile numbers consisting of 9 digits.

I have this pattern of two numbers repeating for 4 times each

5XXXXYYYY 

I was able to write a regex that catches the first group 'XXXX'. However, I am not able to acpture the second one 'YYYY'.

This is the regex I have tried so far

(\d)\1{3}

[0-9]{4,5}

I tried it on the below number, it returns '1111' and ignores '2222'

511112222

Is there a way to repeat the capture to include both groups

Thank you

CodePudding user response：

You may use this regex:

^5((\d)\2{3})((\d)\4{3})$

RegEx Demo

RegEx Breakup:

• ^: Start
• 5: Match 5
• (: Start capture group #1
  • (\d): Match a digit in capture group #2
  • \2{3}: Repeat value captured in group #2 exactly 3 times
• ): End capture group #1
• (: Start capture group #3
  • (\d): Match a digit in capture group #4
  • \4{3}: Repeat value captured in group #4 exactly 3 times
• ): End capture group #3
• $: End