JS Build If (conditions) dynamically according to different array contents-CodePudding

let data1 = [{'id' : '0001', 'area' : 'Paris', 'price' : '100', 'year': '2022'}]
//should construct condition if(id === '0001' && area === 'Paris' && price === '100 && year === '2022')

let data2 = [{'price' : '300', 'year': '2021'}]
//should construct condition if(price === '300' && year === '300')

let data3 = [{'area' : 'Athens'}]
//should construct condition if(area === 'Athens')
// no && when we have only one condition

//my code attempt fo far

let ArrayNew = [];
let operator_and = ' && ';

for(let i = 0; i < data1.length; i  ) {
  ArrayNew  = data1.map(x => Object.keys(x)   ' === '   operator_and);
}

console.log('if ('  ArrayNew  ')'); // if (id,area,price,year ===  && )

Question

I am trying to build dynamically conditions inside an if() statement according not only to the number of keys but also to the keys of each given array.

I expect to create something like this

if (generated_conditions) { .... }

CodePudding user response：

May be try something like this

let data1 = [{'id' : '0001', 'area' : 'Paris', 'price' : '100', 'year': '2022'}]

data1.forEach((item) => {
  let condition = '';
  let keys = Object.keys(item);
  keys.map((k) => {
    if (condition) {
      condition  = ` && ${k} == ${item[k]}`
    } else {
      condition = `${k} == ${item[k]}`
    }

  })
  console.log(condition)
})