How do you access environment variables exported in Bash from inside docker-compose?
I'm essentially trying to do what's described in this answer but I don't want to define a .env
file.
I just want to make a call like:
export TEST_NAME=test_widget_abc
docker-compose -f docker-compose.yml -p myproject up --build --exit-code-from myproject_1
and have it pass TEST_NAME
to the command inside my Dockerfile, which runs a unittest suite like:
ENV TEST_NAME ${TEST_NAME}
CMD python manage.py test $TEST_NAME
My goal is to allow running my docker container to execute a specific unittest without having to rebuild the entire image, by simply pulling in the test name from the shell at container runtime. Otherwise, if no test name is given, the command will run all tests.
As I understand, you can define environment variables in a .env
file and then reference them in your docker-compose.yml like:
version: "3.6"
services:
app_test:
build:
args:
- TEST_NAME=$TEST_NAME
context: ..
dockerfile: Dockerfile
but that doesn't pull from the shell.
How would you do this with docker-compose?
CodePudding user response:
Environment variables in your docker-compose.yaml
will be substituted with values from the environment. For example, if I write:
version: "3"
services:
app_test:
image: docker.io/alpine:latest
environment:
TEST_NAME: ${TEST_NAME}
command:
- env
Then if I export TEST_NAME
in my local environment:
$ export TEST_NAME=foo
And bring up the stack:
$ docker-compose up
Creating network "docker_default" with the default driver
Creating docker_app_test_1 ... done
Attaching to docker_app_test_1
app_test_1 | PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
app_test_1 | HOSTNAME=be3c12e33290
app_test_1 | TEST_NAME=foo
app_test_1 | HOME=/root
docker_app_test_1 exited with code 0
I see that TEST_NAME
inside the container has received the value from my local environment.
It looks like you're trying to pass the environment variable into your image build process, rather than passing it in at runtime. Even if that works once, it's not going to be useful, because docker-compose
won't rebuild your image every time you run it, so whatever value was in TEST_NAME
at the time the image was built is what you would see inside the container.
It's better to pass the environment into the container at run time.
CodePudding user response:
For the setup you describe, I'd docker-compose run
a temporary container
export COMPOSE_PROJECT_NAME=myproject
docker-compose run app_test python manage.py test_widget_abc
This uses all of the setup from the docker-compose.yml
file except the ports:
, and it uses the command you provide instead of the Compose command:
or Dockerfile CMD
. It will honor depends_on:
constraints to start related containers (you may need an entrypoint wrapper script to actually wait for them to be running).
If the test code is built into your "normal" image you may not even need special Compose setup to do this; just point docker-compose run
at your existing application service definition without defining a dedicated service for the integration tests.
Since Compose does (simple) environment variable substitution you could also provide the per-execution command:
in your Compose file
version: "3.6"
services:
app_test:
build: ..
command: python manage.py $TEST_NAME # uses the host variable
Or, with the Dockerfile you have, pass through the host's environment variable; the CMD
will run a shell to interpret the string when it starts up
version: "3.6"
services:
app_test:
build: ..
environment:
- TEST_NAME # without a specific value here passes through from the host
These would both work with the Dockerfile and Compose setup you show in the question.