My code

cummulative_num = [['1', '4', '5', '7'], ['2', '5', '6', '9']]

if len(cumulative_num)==1:
    print(*cumulative_num[0])
out=""
if len(cumulative_num)==2:
    for i in cumulative_num[0]:
        for j in cumulative_num[1]:
            out = i j  " "
print(out)
out=""
if len(cumulative_num)==3:
    for i in cumulative_num[0]:
        for j in cumulative_num[1]:
            for k in cumulative_num[2]:
                out = i j k  " "
print(out)

output : 12 15 16 19 42 45 46 49 52 55 56 59 72 75 76 79

Here the output order should be each first array element is added to every element in the second array

Please provide me a Better approach when the array in cummulative_num increases.

CodePudding user response：

Something like this could work:

The * unpacks the lists into product, no matter how many sublists you may have.

from itertools import product
cummulative_num = [['1', '4', '5', '7'], ['2', '5', '6', '9']]
' '.join([''.join(x) for x in product(*cummulative_num)])

Output

'12 15 16 19 42 45 46 49 52 55 56 59 72 75 76 79'

CodePudding user response：

This code is nothing fancy, but it works well and can be adapted well depending on if you want the data stored.

output = [] #Optional
for i in cummulative_num[0]:
    for j in cummulative_num[1]:
        output.append(f'{i}{j}') #Optional
        print(f'{i}{j}')