import java.util.ArrayList;
import java.util.Arrays;

public class DivisiveArrayOfNumbers {
    public int[] solution(int divisor, int[] arr) {
        int[] answer;
        ArrayList<Integer> a1 = new ArrayList<Integer>();

        for (int i = 0; i < arr.length; i  ) {
            if (arr[i] % divisor == 0)
                a1.get(i);
        }

        if (a1.isEmpty()) {
            a1.add(-1);
        }

        answer = new int[a1.size()];
        for (int i = 0; i < a1.size(); i  ) {
            answer[i] = a1.get(i);
        }
        Arrays.sort(answer);
        return answer;
    }

    public static void main (String[] args) {
        DivisiveArrayOfNumbers method = new DivisiveArrayOfNumbers();
        System.out.println(method.solution(5, new int{}{5, 9, 7, 10, 5}));
    }

}

I want to put it together int, int[] in "method.solution( )".

but the following error appears.

I want to make it recognized as int[] type, is there a way?

enter image description here

I saw the comments and corrected them :)

CodePudding user response：

Try:

System.out.println(Arrays.ToString(method.solution(5, new int[]{9, 7, 10, 5}))); 

CodePudding user response：

You can achieve this by

public int[] solution(int divisor, int[] arr)
{
    
    System.out.println(Arrays.toString(arr));
    return arr;
}

public static void main (String[] args) {
    Index method = new Index();
    System.out.println(method.solution(5, new int []{9, 7, 10,5}));
}

output

[9, 7, 10, 5]
[I@15db9742

CodePudding user response：

The issue you are having is that you did not pass the right number of arguments.

As you can see from the first line, solution(int divisor, int[] arr) has two arguments. You know this because there is one comma that separates the divisor parameter from the arr parameter.

You attempted to call method.solution(5, 9, 7, 10,5). As you can see, there are 5 arguments separated by 4 commas.

What you want is to group the last 4 arguments together into an array as evident by the type of the second argument: int[]

This is the shorthand way of making an array new int[]{9, 7, 10, 5}

You may be more familiar with int[] myArray = {9, 7, 10, 5}

You can call the function in one of two ways:

int[] myArray = {9, 7, 10, 5};
System.out.println(method.solution(5, myArray));

or

System.out.println(method.solution(5, new int []{9, 7, 10,5}));