import random as r

print(
"""
        Welcome to the Custom Counter!
    
    Type in your starting value and your
    ending value. Then, enter the amount
    by which to count.
""")

x = True

start = int(input("Starting number: "))
while x != False or start != "":
    fin = int(input("Ending number: "))
    amount = int(input("Count by: "))
    if amount > 0 or amount < 0:
        x = False
        
result = r.randrange(start, fin, amount)    
print(result)

input("Hit enter to exit.")

I made the while loop in hopes to exit the program when you clicked enter. Unfortunately, this will not let me exit the while loop no matter what I do. I am a noob at python. What is wrong with my condition?

Thank you!

CodePudding user response：

Welcome to stackoverflow and welcome to Python!

Try to use and instead of or.

In your line:

while x != False or start != "":

You say to python, you want to run until 1st or 2nd condition is true. Since the 2nd condition stays always true, while will run forever.

Even more simple:

while x and start:

Hope you will enjoy Python as I do!

CodePudding user response：

my code :

import random as r

print(
"""
        Welcome to the Custom Counter!
    
    Type in your starting value and your
    ending value. Then, enter the amount
    by which to count.
""")


while True:
    
    try:
        start = int(input("Starting number: "))
        fin = int(input("Ending number: "))
        amount = int(input("Count by: "))
    
    except ValueError as verr:
        
        print('error : ', verr,'\n restarting ....')
        
    else:
        
        break
        
   
result = r.randrange(start, fin, amount)    
print('result : ' ,result)

input("Hit enter to exit.")

this one I believe takes into account inputting of non ints and restart program from scratch when encountering such kind of inputs.

See The try statement specifies exception handlers and/or cleanup code for a group of statements

PS your code doesnt handle invalid values (i.e. fin < start)