How to get the filtered data with two or more return values with function includes-CodePudding

var arr1 = [
  "T-1",
  "CAT"
]

var arr2 = [
  "Lemuel F (T-1)",
  "Levi C (T-1)",
  "Monfel (T-2)",
  "JC (T-1)",
  "Wrecker (CAT)"
]

const arr3 = arr2.filter(a => {
  return (a.includes(arr1[0]));
});
console.log("arr3", arr3);

This is the output I get :

[ 'Lemuel F (T-1)', 'Levi C (T-1)', 'JC (T-1)' ]

This is the output I'm trying to get

[ 'Lemuel F (T-1)', 'Levi C (T-1)', 'JC (T-1)','Wrecker (CAT)' ]

I'm trying to use multiple includes but I still cant find a way. I've tried this syntax

 return (a.includes(arr1[0]) && (a.includes(arr1[1]

CodePudding user response：

Answering your question here is how to use include in your situation, however I also recommend using regex, since it simplifies the issue quite a bit and only requires you to iterate over each element once.

const arr1 = ["T-1", "CAT"];

const arr2 = [
  "Lemuel F (T-1)",
  "Levi C (T-1)",
  "Monfel (T-2)",
  "JC (T-1)",
  "Wrecker (CAT)"
];

// using includes
const arr3 = arr2.filter((value2) => arr1.some((value1) => value2.includes(value1)));
console.log(arr3);

// using regex
const regex = new RegExp(arr1.join("|"), "g");
const arr4 = arr2.filter((value) => value.match(regex));
console.log(arr4);

CodePudding user response：

A quick solution that can be used for your case is to have a Regular Expression that tests for the existence of the substrings inside the sentences array.

const subStrings = ["T-1", "CAT"],
  strings = ["Lemuel F (T-1)", "Levi C (T-1)", "Monfel (T-2)", "JC (T-1)", "Wrecker (CAT)"],
  /** 
   * create a RegExp object on the fly
   * the "|" token acts like the logical OR operator
   * basically we'll have this regex: "T-1|CAT"
   */
  regExp = new RegExp(subStrings.join('|')),
  res = strings.filter(s => regExp.test(s));

console.log(res);

CodePudding user response：

You're basically looking at an array intersection (arr1 × arr2), but with some slightly tweaked logic as you want the predicate to look at the string inside the parenthesis in arr2. You can use regex to extract the keyword you want to match (that is encapsulated between parenthesis), and check if it exists in arr1:

arr2.filter(entry => {
  const keyword = entry.match(/\(([^)] )\)/)[1];
  return arr1.includes(keyword);
});

Here is a proof-of-concept example based on your code, which returns the data as you expect:

const arr1 = ["T-1", "CAT"];

const arr2 = [
  "Lemuel F (T-1)",
  "Levi C (T-1)",
  "Monfel (T-2)",
  "JC (T-1)",
  "Wrecker (CAT)",
];

const arr3 = arr2.filter(entry => arr1.includes(entry.match(/\(([^)] )\)/)[1]));
console.log(arr3);

CodePudding user response：

const arr3 = arr2.filter(item=>arr1.some(item2=>item2.includes(item)))