Directory Content Count Using Linux Find Command-CodePudding

How can I populate the placeholder [COUNT] in the following Linux find command with total number of files plus folders for each sub-directory inside SomeFolder where am using bash:

find '/SomeFolder' -maxdepth 1 -mindepth 1 -type d -printf '%f **[COUNT]**\n' | sort

CodePudding user response：

If you use find just to print out the directories, then pipe the output to xargs to produce the counts, you could write it like this:

find '/SomeFolder' -maxdepth 1 -mindepth 1 -type d -print0 |
  xargs -0 -IDIR sh -c 'echo "$(basename "DIR"): $(ls "DIR" | wc -l)"' |
  sort

Which gets you output like:

android-otp-extractor: 1
ansible: 13
argocd-app-of-app-chart: 1
asan: 0
asm: 0
aws-secrets: 0
backup: 0

But as @Jetchisel said, you don't really need find for what you're doing; this should get you the same thing:

ls --zero -d /SomeFolder/*/ |
  xargs -0 -IDIR sh -c 'echo "$(basename "DIR"): $(ls "DIR" | wc -l)"' |
  sort

(We're using --zero with ls and -print0 with find in order to correctly handle directory names that contain whitespace.)

CodePudding user response：

Not sure if find is really needed with globstar on with bash but, here it is.

#!/usr/bin/env bash

count=0

while IFS= read -rd '' sub_dirs; do
  shopt -s globstar nullglob dotglob
  count=("$sub_dirs"/**)
  shopt -u globstar nullglob dotglob
  printf '%s: %d\n' "$sub_dirs" "${#count[*]}"
done < <(find /Somedir -maxdepth 1 -mindepth 1 -type d -print0) |
sort -k2 -n