How can I replace string in list using dictionary?

I have

text = ["h#**o "," &&&orld"]

replacement = {"#":"e","*":"l"," ":"w","&":""}

I want:

correct = ["Hello World"]

I have try:

def correct(text,replacement):
    for word, replacement in replacement.items():
        text = text.replace(word, replacement)

But: AttributeError: 'list' object has no attribute 'replace'

CodePudding user response：

What you have is mostly correct except your correct function seems to be wanting to correct only a single str (e.g. "h#**o " => "hellow"), whereas your variable text is currently a list or strs. So if you want to get "hellow world" you need to call correct multiple times to get a list of corrected words, which you can then join into a string.

Try this runnable example!

#!/usr/bin/env python

words = ["h#**o "," &&&orld"]
replacement = {"#":"e","*":"l"," ":"w","&":""}

def correct(text,replacement):
    for word, replacement in replacement.items():
        text = text.replace(word, replacement)
    return text

def correct_multiple(words, replacement):
    new_words = [correct(word, replacement) for word in words] # get a list of results
    combined_str = " ".join(new_words) # join the list into a string
    return combined_str

output = correct_multiple(words, replacement)
print(f"{output=}")

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CodePudding user response：

You can do this too:

text = ["h#**o "," &&&orld"]
replacement = {"#":"e","*":"l"," ":"w","&":""}

string1 = " ".join(text)  # join the words into one string
string2 = string1.translate(string1.maketrans(replacement))
string3 = string2.title()

print(string1   '\n'   string2   '\n'   string3)
# h#**o   &&&orld
# hellow world
# Hellow World

I've separated the proceedings into 3 successive steps to demonstrate the effect of each step.

CodePudding user response：

text is a LIST of strings, not a string. You can't call string methods on it.

text[0].replace() would be a thing...