Getting last two digits of Sequence Date in R-CodePudding

I have sequence date:

names<-format(seq.Date(as.Date("2012-11-01"),as.Date("2012-12-01"),
                by = 'months'),format = "%Y%m")

How can I get the last two digit, like the result for last two digits of names[1] is 11?

CodePudding user response：

Using the stringr package you can just put

stringr::str_sub(string = names, start = -2, end = -1)

CodePudding user response：

You could use substr():

names = substr(names, nchar(names)-1, nchar(names))

The result is:

[1] "11" "12"

Or as integer:

names = as.integer(substr(names, nchar(names)-1, nchar(names))

Result:

[1] 11 12

CodePudding user response：

There can be tenths of ways. The simpliest I could invent was to find the remainder of intiger division:

as.integer(names)  %% 100

that returns:

[1] 11 12

Technically these are integers. If you stricktly require characters apply as.character() to the result to cast the type.