how to remove the end for =0 in latex algorithm?-CodePudding

I didn't find how to remove the "=0" after the end for. I find some people recommended to delete \usepackage[noend]{algpseudocode}, but the indentation will be lost in this case. Is there another alternative?

\documentclass[3p,times]{article}

\usepackage{algorithm,algorithmic}
\usepackage[noend]{algpseudocode}

\begin{document}

\begin{algorithm}[H]
    \caption{caption}\label{algorithm_1}
    \begin{algorithmic}[1]
        \STATE  $\mathrm{initialization}$
        \FOR{steps = $1$ to $N$}

            \WHILE{condition 1}
                \STATE compute solution 
                \If{condition} 
                    \State do  1
                \Else
                    \If{condition 2}
                        \State do 2 
                    \Else 
                    \State  do 3
                    \EndIf
                \EndIf 
            \ENDWHILE
        \ENDFOR ~
    \end{algorithmic}
\end{algorithm}




\end{document}

I tried to use the package algorithm2e, but that does not fix the problem. the package algpseudocode is mandatory for the indentation of the algorithm

CodePudding user response：

Your document does not compile. It throws the error

Command \algorithmic already defined. }

After an error, latex only syntax checks the rest of the document, not necessarily producing sensible output. There is no point in worrying about a stray =0 if there are still errors in your document. You should instead fix the package incompatibilities.

Your combination of syntaxes from different packages (\STATE vs. \State etc.) makes this a bit difficult, but the following seems to work:

\documentclass{article}
\usepackage{float}
\usepackage{algorithm}
\usepackage{algorithmicx}
\usepackage[noend]{algpseudocode}

\begin{document}

\begin{algorithm}[H]
    \caption{caption}\label{algorithm_1}
    \begin{algorithmic}[1]
        \State  $\mathrm{initialization}$
        \For{steps = $1$ to $N$}

            \While{condition 1}
                \State compute solution 
                \If{condition} 
                    \State do  1
                \Else
                    \If{condition 2}
                        \State do 2 
                    \Else 
                    \State  do 3
                    \EndIf
                \EndIf
            \EndWhile
        \EndFor
    \end{algorithmic}
\end{algorithm}

\end{document}