Comparing dictionary of list of dictionary/nested dictionary-CodePudding

There are two dict main and input, I want to validate the "input" such that all the keys in the list of dictionary and nested dictionary (if present/all keys are optional) matches that of the main if not the wrong/different key should be returned as the output.

main = "app":[{
    "name": str,
    "info": [
        {
        "role": str,
        "scope": {"groups": list}
        }
        ]
    },{
    "name": str,
    "info": [
        {"role": str}
            ]
}]

input_data = "app":[{
    'name': 'nms',
    'info': [
        {
        'role': 'user',
        'scope': {'groups': ['xyz']
                }
        }]
},{
    'name': 'abc', 
    'info': [
    {'rol': 'user'}
    ]
}]

when compared input with main the wrong/different key should be given as output, in this case

['rol']

CodePudding user response：

The schema module does exactly this. You can catch SchemaUnexpectedTypeError to see which data doesn't match your pattern.

Also, make sure you don't use the word input as a variable name, as it's the name of a built-in function.

CodePudding user response：

keys = []
def print_dict(d):
    if type(d) == dict:
        for val in d.keys():
            df = d[val]
            try:
                if type(df) == list:
                    for i in range(0,len(df)):
                        if type(df[i]) == dict:
                            print_dict(df[i])
            except AttributeError:
                pass
            keys.append(val)
    else:
        try:
            x = d[0]
            if type(x) == dict:
                print_dict(d[0])
        except:
            pass
    return keys
keys_input = print_dict(input)
keys = []
keys_main = print_dict(main)
print(keys_input)

print(keys_main)

for i in keys_input[:]:
        if i in keys_main:
            keys_input.remove(i)
print(keys_input)

This has worked for me. you can check above code snippet and if any changes provide more information so any chances if required.